A wheel has a rotational inertia of 16 kgm2. Over an interval of 2.0 s its angular

128.61 Watts

Explanation:

Average power done by the torque is expressed as the ratio of the workdone by the toque to time.

Power = Workdone by torque/time

Workdone by the torque = =

I is the rotational inertia = 16kgm²

To get the angular acceleration, we will use the formula;

Workdone by the torque = 16 * 1.28 * 12.56

Workdone by the torque = 257.23 Joules

Average power done by the torque = Workdone by torque/time

=  257.23/2.0

= 128.61 Watts

So what my teacher has taught me that me a lot is to make a suvat table, which goes like
s(distance-m) - unknown
u(initial velocity-m/s) - 0m/s, we know this because it says it started from rest.
v(final velocity-m/s) - 10m/s, it states 10m/s as the final velocity
a(acceleration-m/s^2) - unknown
t(time-s) - 4 seconds, as stated
now, with this information, we can use one of the following equations to
v=u+at
v^2=u^2+2as
s=ut+(1/2)at^2
with the of these equations, we can solve basically any suvat problem. with the information we have, to find acceleration, it would be best to use the first equation to solve the problem.

simplify, and solve for a, which
10=a4
a=(5/2)m/s^2

i hope this ! if you have more questions on physics, feel free to contact me. message me if you want contact info.