Chemistry
31.03.2021 20:17
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A stock solution will be prepared by mixing the following chemicals together: 3.0

A stock solution will be prepared by mixing the following chemicals together: 3.0 mL of 0.00200 M KSCN
10.0 mL of 0.200 M Fe(NO3)3
17.0 mL of 0.5 M HNO3

Determine the molar concentration of Fe(NO3)3 in the stock solution.
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rosebelll4555
rosebelll4555
4,5(43 marks)

0.067M Fe(NO3)3

Explanation:

A stock solution is a concentrated solution that is diluted to prepare the solutions that you will use.

The volume of the stock solution is 3.0mL + 10.0mL + 17.0mL= 30.0mL.

The ratio between volume of the aliquot (10.0mL) and total volume (30.0mL) is called dilution factor, that is: 30.0mL / 10.0mL = 3

That means the Fe(NO3)3 is diluted 3 times. That means the molar concentration of the stock solution is:

0.200M / 3 =

0.067M Fe(NO3)3
saucyboyFredo
saucyboyFredo
4,8(77 marks)

I say the statement is true

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