Physics
02.11.2021 20:42
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A speed skater is sliding across the ice at a speed of 19 m/s when she encounters

A speed skater is sliding across the ice at a speed of 19 m/s when she encounters a rough patch of ice that is 2.0 m wide. As she coasts out of the rough patch, she is moving with a speed of 18 m/s. Assuming her deceleration to be constant, roughly what is the magnitude of that deceleration?
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elreemali03
elreemali03
4,5(83 marks)

-9.25 m/s^2

Explanation:

The motion of the skater is a uniformly accelerated motion, so we can find the deceleration by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

In this problem, we have:

u = 19 m/s is the initial velocity of the skater

v = 18 m/s is the final velocity of the skater

s = 2.0 m is the displacement

Solving for a, we can find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{18^2-19^2}{2(2.0)}=-9.25 m/s^2

And the negative sign tells us that the acceleration is in the opposite direction to the motion (so, it is a deceleration)

nicollexo21
nicollexo21
4,6(36 marks)

It goes inside filling most of it .

Explanation: This happens because the bottle is empty and the bucket is full of water.

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