Physics
14.08.2020 20:40
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A second identical block, with twice the mass and twice the surface area as the

A second identical block, with twice the mass and twice the surface area as the original block is placed on the same horizontal board with the original block. One end of the level board is now slowly raised. Which block, if any, is the first to slip and begin to slide down the board? Justify your answer. Equations may be part of your reasoning, but equations alone are not sufficient justification.
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hannahsambrano12
hannahsambrano12
4,8(16 marks)

1.5min

Explanation:

To solve the problem it is necessary to take into account the concepts related to Period and Centripetal Acceleration.

By definition centripetal acceleration is given by

a_c = \frac{V^2}{r}

Where,

V = Tangencial velocity

r = radius

With our values we know that

a_c = \frac{V^2}{r}

\frac{V^2}{r} = \frac{1}{10}g

Therefore solving to find V, we have:

V = \sqrt{\frac{1}{10}g*r}

V = \sqrt{\frac{9.81*200}{10}}

V = 14m/s

For definition we know that the Time to complete are revolution is given by

t = \frac{Perimeter}{Speed}

t = \frac{2\pi R}{V}

t = \frac{2\pi * 200}{14}

t = 1.5min

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