Mathematics
10.08.2021 09:42
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a rectangle has a length of 8 and a width of 4. four equal rectangles are drawn

a rectangle has a length of 8 and a width of 4. four equal rectangles are drawn within that rectangle, creating the longest lengths possible for the rectangles. what is the sum of the perimeters of two of these equal rectangles?
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bludragonfly33
bludragonfly33
4,4(55 marks)

Given:

A rectangle has a length of 8 and a width of 4.

Four equal rectangles are drawn within that rectangle, creating the longest lengths possible for the rectangles.

To find:

The sum of the perimeters of two of these equal rectangles.

Solution:

We have to draw 2 lines which are bisecting the length and width respectively, to divide a rectangle in 4 equal parts with longest lengths.

Half of length 8 = 4

Half of width 4 = 2

It means each rectangle have a length of 4 and a width of 2.

Perimeter of a rectangle is

Perimeter=2(length+width)

Perimeter=2(4+2)

Perimeter=2(6)

Perimeter=12

So, perimeter of each equal rectangle is 12 units.

Sum of the perimeters of two of these equal rectangles is

12+12=24

Therefore, sum of the perimeters of two of these equal rectangles is 24.

raerea2005
raerea2005
4,7(73 marks)

33 miles

Step-by-step explanation:

The cyclist traveled for 3 hours ar 11 miles per house to find how many miles she traveled simply multiply the speed times the amount of time traveled 11 times 3 is 33

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