Physics
21.04.2020 17:24
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A particle moves in a circular path of radius 0.10 m with a constant angular speed

A particle moves in a circular path of radius 0.10 m with a constant angular speed of 5 rev/s. The acceleration of the particle is:
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juniorvalencia4
juniorvalencia4
4,4(63 marks)

Explanation:

The Formula for finding the centripetal force F_{c}is following

F_{c} = \frac{mv^{2} }{r}

From the question, mass m and radius r is given. However, we have to find the velocity v;

using formula

2*π*r=C

putting values

C = 2*3.14*(1.5 * 10^{8} * 10^{3}  )

C= 9.425 * 10^{11}

Using formula

C=v*t

v=\frac{C}{t} \\v=\frac{9.425*10^{11}  }{365.25<img src=}" alt="*24*60*60" />}" />

v = 29866.02m/s

putting in formula of F_{c}[tex],</p<p[tex]F_{c} = \frac{6*10^{24} * 10^{3}  * (29866.02^{2} )}{1.5*10^{11} }

F_{c} = 3.5679*[tex]10^{22}

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