Mathematics
28.12.2021 08:01
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A parabola-shaped hill can be modeled by equation y=-2(x - 3)2 +6, where x and y

A parabola-shaped hill can be modeled by equation y=-2(x - 3)2 +6, where x and y are measured in
kilometers.
How wide is the bottom of the hill? Assume the r -axis is
ground level. Round to the nearest tenths.
kilometers
Show Answers
shawn4544
shawn4544
4,5(37 marks)

3.46 km

Step-by-step explanation:

Given

shape of hill y=-2(x-3)^2+6

at the bottom y=0 i.e.

0=-2(x-3)^2+6\\(x-3)^2=3\\x-3=\pm\sqrt{3}\\x=3\pm\sqrt{3}

width of the bottom

3+\sqrt{3}-[3-\sqrt{3}]=2\sqrt{3}\ km\ or\ 3.46\ km

palmtree2759
palmtree2759
4,9(15 marks)

Trace a line between the intersection of the two circles.

Step-by-step explanation:

This is a very important technique, the next thing you do is trace a line in between the intersection of the circles and that would intercept your circle. I will show you in a drawing.


Erik is bisecting a segment with technology. Which of the following describes his next step? Draw a

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