let Tension in the left chain is F
here, Fnet = 0
βF - 500N + 250 N - 125 N = 0
βF - 375 N = 0
βF = 375 N
let r from the left end of the board is the person sitting.
now torque at left end, Ο = 0.
β375 Γ (0) - 500N Γ (r) + 250N Γ (4m) - 125 N Γ (2m) = 0
β0 - 500r + 1000 - 250 = 0
β750 = 500r
βr = 750/500 = 1.5 m
Explanation:
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Explanation: