Physics
16.08.2020 14:55
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A goal should NOT be:

A goal should NOT be:
A goal should NOT be:
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naenaekennedybe
naenaekennedybe
4,4(28 marks)
Unspecific

A goal should NOT be unspecific
alyssamiller401
alyssamiller401
4,9(44 marks)

The magnitude of the resultant vectors is 64.69 cm

The  direction of the vector of the vector is 332.4 ⁰ north west

The given parameters;

displacement \ at \ 90^0 = 83 \ cm\\\\displacement \ at \ 147^0 = 59 \ cm\\\\displacement \ at \ 221^0 = 69 \ cm\\\\displacement \ at \ 283^0 = 45 \ cm\\\\displacement \ at \ 27^0 = 69 \ cm

The resultant displacement is calculated by resolving each vector into x and y components.

The y-component of the vectors assuming all vectors are measured counter-clockwise from x-axis;

R_y = (83\times sin(90)) + (59\times sin(147)) + (69\times sin(221)) + (45\times sin(283))\\ \ \ \ . \ \ \ \ \ \ + (69\times sin(27)) \\\\R_y = (83) + (32.13) + (-45.27) + (-43.85) + (31.33)\\\\R_y = (57.34) j

The x-component of the vectors

R_x = (83\times cos(90)) + (59\times cos(147)) + (69\times cos(221)) + (45\times cos(283))\\ \ \ \ . \ \ \ \ \ \ + (69\times cos(27)) \\\\R_x = (0) + (-49.48)  + (-52.07) + (10.12) + (61.48)\\\\R_x = (-29.95) i

The magnitude of the resultant vectors is calculated as;

|R| = \sqrt{R_y^2 + R_x^2} \\\\|R| = \sqrt{(57.34)^2 + (-29.95)^2} \\\\|R| = 64.69 \ cm

The direction of the vector;

\theta = tan^{-1} (\frac{R_y}{R_x} )\\\\\theta = tan^{-1} (\frac{57.34}{-29.95} )\\\\\theta = tan^{-1} (-1.915) = -62.4^0 = 332.4 ^0 \ north \ west

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