A Fraunhofer diffraction pattern is produced on a screen 1.30 m from a single slit.

The value is

Explanation:

From the question we are told that

    The distance from the screen is  D =  1.30 m

    The wavelength of the light source is  

     The path difference is mathematically represented as  

Generally the path difference is mathematically represented as

       

Here m is 1 given that we are considering the first dark fringe

So  

       

=>    

=>    

=>    

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