Answer 1: the charge on the plates will increase
Explanation: placing a dielectric between two charged plate increases its capacitance
C = Q/V,
If the plates remain connected then the voltage remains the same.
Therefore for an increase in capacitance charge will increase.
Answer 2: electric field potential remains the same.
Explanation: if the plates are disconnected, charge on plates remains contant while voltage varies with change in distance, electric field intensity remains constant and this is proportional to the electric potential energy.
Answer 3: capacitance increases
Explanation: introducing a dielectric between two plates causes opposite charges to be induced on the faces of the dielectric. This also reduces the p.d across the capacitor.
Answer 4: voltage remains constant.
Explanation: A connected plate has a constant voltage across its field.
Answer 5: charge remains contant.
Explanation: capacitance will increase with introduction of dielectric, p.d across the plates will drop, the charge will remain constant.
Answer 6: capacitance increases
Explanation: placing a dielectric between plates always increase the capacitance.
Answer 7: electric potential energy falls.
Answer 8: voltage between plates decreases
The speed of the block is 1.65 m/s.
Explanation:
Given that,
Radius = 12 cm
Mass of pulley= 360 g
Mass of block = 70 g
Distance = 50 cm
(a). We need to calculate the speed
Using energy conservation
Put the value into the formula
(b), We need to calculate the speed of the block
When r = 5.0 cm
Here, The speed of the block is independent of radius of pulley.
Hence, The speed of the block is 1.65 m/s.