A cylindrical rod with length (1.7 m) and radius (2 cm) is fixed from one end and

0.44

Explanation:

Poisson's ratio is:

ν = (3K − E) / 6K

where K is the bulk modulus and E is Young's modulus.

Young's modulus is:

E = FL / (AΔL)

where F is the force, L is the initial length, A is the cross sectional area, and ΔL is the change in length.

E = (20 kg × 9.8 m/s²) (1.7 m) / (π (0.02 m)² × 0.0005 m)

E = 0.530×10⁹ Pa

Bulk modulus is:

K = -ΔP / (ΔV/V)

where ΔP is the change in pressure, ΔV is the change in volume, and V is the initial volume.

K = -(180 atm × 101325 Pa/atm) / (-0.012)

K = 1.52×10⁹ Pa

Therefore, the Poisson's ratio is:

ν = (3(1.52×10⁹ Pa) − 0.530×10⁹ Pa) / 6(1.52×10⁹ Pa)

ν = (3(1.52) − 0.530) / 6(1.52)

ν = 0.442

Rounded to 2 significant figures, the Poisson's ratio is 0.44.

The answer is B i know this because

superficial anatomy of the circulatory system

functional anatomy of the circulatory system

superficial anatomy of the nervous system

functional anatomy of the nervous system

its not a nervous system part so there goes the last two and superfical means from the outside of the body like skin and hair and the reproductive like testicals and and the ovarys stuff like that thus leaves your answer with the only logical one {functional anatomy of the circularory system}.