Physics
26.04.2021 02:35
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A brass rod with a mass of 0.300 kg slides on parallel horizontal iron rails, 0.440

A brass rod with a mass of 0.300 kg slides on parallel horizontal iron rails, 0.440 m apart, and carries a current of 15.0 A. The coefficient of friction between the rod and rails is 0.300. What vertical, uniform magnetic field is needed to keep the rod moving at a constant speed
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josmanu235
josmanu235
4,5(13 marks)

The magnitude of the magnetic field is  B  =  0.0890 \ T

Explanation:

From the question we are told that

   The mass of the rod is  m =0.300 \ kg

    The distance of separation is  d = 0.440 \ m

     The current is  I  = 15.0 \ A

     The coefficient of friction is   \mu  =  0.300

     

Generally for the rod the rod to continue moving at a constant speed

   The frictional force must equal to the magnetic field force so

    F_m =  F_f

Where  F_m  =  B* I * d

and     F_f  =  \mu * m * g

   B*I *d =  \mu * m * g

=>    B  =  \frac{\mu * m * g }{I  * d }

substituting values

       B  =  \frac{0.2  * 0.300 * 9.8 }{ 15   * 0.440 }

       B  =  0.0890 \ T

knussoshd3603
knussoshd3603
4,4(19 marks)

Anthony will be warmer after the game because he is wearing a black shirt. Dark colors absorb more thermal energy than light colors.

Explanation:

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