Physics
03.11.2022 05:24
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A balanced three-phase 60 Hz source supplies power to a balanced A-connected inductive

A balanced three-phase 60 Hz source supplies power to a balanced A-connected inductive load. The line voltage is 440 V, the line current is 8.2 A, and the power delivered to the load is 5 kW.

(a) Calculate the load impedance per phase.
(b) Find the complex power generated by the source
(c) What should be done to increase the power factor to unity? Give the value of any component added to the circuit (per phase).
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shiba8667
shiba8667
4,8(86 marks)

The impedance per phase is 1.25H. This was calculated using the ... the complex power generated is 3.4kw. The full solution can be found below.

Explanation:

alexamorantess
alexamorantess
4,4(59 marks)

The other angle is 75⁰

Explanation:

Given;

velocity of the projectile, v = 10 m/s

range of the projectile, R = 5.1 m

angle of projection, 15⁰

The range of a projectile is given as;

R = \frac{u^2sin(2\theta)}{g}

To find another angle of projection to give the same range;

5.1 = \frac{10^2 sin(2\theta)}{9.81} \\\\100sin(2\theta) = 50\\\\sin(2\theta) = 0.5\\\\2\theta = sin^{-1}(0.5)\\\\2\theta = 30^0\\\\\theta = 15^0\\\\since \ the \ angle \ occurs \ in \ \ the \ first \ quadrant,\  the \ equivalent \ angle \\ is \ calculated \ as;\\\\90- \theta = 15^0\\\\\theta = 90 - 15^0\\\\\theta = 75^0

Check:

sin(2θ) = sin(2 x 75) = sin(150) = 0.5

sin(2θ) = sin(2 x 15) = sin(30) = 0.5

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