A 3.0kg cat and a 14kg dog exert a force of gravity on each other equal to 1.12
The expression for the gravitational force between two bodies is given by:
where,
G: Cavendish's constant = 6.67*10-11Nm^2/kg^2
m1 = 3.0kg
m2 = 14kg
Solve the equation above for r:
![\begin{gathered} r=\sqrt{\frac{Gm_1m_2}{F}} \\ r=\sqrt[]{\frac{(6.67\cdot10^{-11}\frac{Nm^2}{\operatorname{kg}^2})(3.0kg)(14kg)}{10\cdot10^{-10}N}} \\ r\approx1.67m \end{gathered}](/tpl/images/2928/0150/b2d41.png)
Hence, the distance between the dog and the car is approximately 1.67m
Explanation:
To find the acceleration in each trial, we have to apply Newton's Law:
Object 1:Object 2:First, we know that 1kg equals 1000 grams. So, 100 grams, how much kilograms would be:
Object 3:Applying the same transformation, we know that 10 grams equals 0.010 kg.
Object 4:So, comparing each result we observe that the third object has the greatest acceleration, due to its lower mass, because the relation states that the smaller the mass of the object, the higher acceleration would be, because they are inversely proportional, that is, when one magnitude increases, the other decreases.
Therefore, the answer is Object 3.
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