Physics
03.08.2020 10:49
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A 0.400-kg mass is attached to a spring and set into simple harmonic motion. if

A 0.400-kg mass is attached to a spring and set into simple harmonic motion. if its period is 1.7 seconds, what is the spring constant?
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deepspy599otchpd
deepspy599otchpd
5,0(59 marks)

The spring constant is 5.46N/m.

Explanation:

The period T of the mass in SHM is related to the spring constant k by the equation

T = 2\pi \sqrt{\dfrac{m}{k} },

using this we solve for k to get:

k = \dfrac{4\pi ^2m}{T^2}.

For our case we put in m = 0.400kg and T = 1.7s:

k = \dfrac{4\pi ^2(0.400kg)}{(1.7s)^2}.

\boxed{k = 5.46N/m}

which is our spring constant.

tj361
tj361
4,4(19 marks)

so what is 5 * 20 you would want to add it up just so you know the meters is the pounds and you can just add it to kilograms and that's all you need to know about meters and kilograms and grams just in for you know and it's like a night it's actually like yes 20 distance and it's like 17 distances from away

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