Mathematics
10.01.2023 13:45
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8y + 10 βˆ’ 4 βˆ’ 5y = please answer

8y + 10 βˆ’ 4 βˆ’ 5y =

please answer
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paisley13
paisley13
4,4(56 marks)

Well, The best answer will be is y = 2. Good Luck!

ronaldhernandez598
ronaldhernandez598
4,9(74 marks)

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:

24x2+25xβˆ’47=(βˆ’8xβˆ’3)(axβˆ’2)βˆ’53

You should then multiply (βˆ’8xβˆ’3) and (axβˆ’2) using FOIL.

24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16x+6βˆ’53

Then, reduce on the right side of the equation

24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16xβˆ’47

Since the coefficients of the x2-term have to be equal on both sides of the equation, βˆ’8a=24, or a=βˆ’3.

The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and

Step-by-step explanation:

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:24x2+25xβˆ’47=(βˆ’8xβˆ’3)(axβˆ’2)βˆ’53

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:24x2+25xβˆ’47=(βˆ’8xβˆ’3)(axβˆ’2)βˆ’53You should then multiply (βˆ’8xβˆ’3) and (axβˆ’2) using FOIL.

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:24x2+25xβˆ’47=(βˆ’8xβˆ’3)(axβˆ’2)βˆ’53You should then multiply (βˆ’8xβˆ’3) and (axβˆ’2) using FOIL.24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16x+6βˆ’53

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:24x2+25xβˆ’47=(βˆ’8xβˆ’3)(axβˆ’2)βˆ’53You should then multiply (βˆ’8xβˆ’3) and (axβˆ’2) using FOIL.24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16x+6βˆ’53Then, reduce on the right side of the equation

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:24x2+25xβˆ’47=(βˆ’8xβˆ’3)(axβˆ’2)βˆ’53You should then multiply (βˆ’8xβˆ’3) and (axβˆ’2) using FOIL.24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16x+6βˆ’53Then, reduce on the right side of the equation24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16xβˆ’47

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:24x2+25xβˆ’47=(βˆ’8xβˆ’3)(axβˆ’2)βˆ’53You should then multiply (βˆ’8xβˆ’3) and (axβˆ’2) using FOIL.24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16x+6βˆ’53Then, reduce on the right side of the equation24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16xβˆ’47Since the coefficients of the x2-term have to be equal on both sides of the equation, βˆ’8a=24, or a=βˆ’3.

ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by axβˆ’2 (so you can get rid of the fraction). When you multiply each side by axβˆ’2, you should have:24x2+25xβˆ’47=(βˆ’8xβˆ’3)(axβˆ’2)βˆ’53You should then multiply (βˆ’8xβˆ’3) and (axβˆ’2) using FOIL.24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16x+6βˆ’53Then, reduce on the right side of the equation24x2+25xβˆ’47=βˆ’8ax2βˆ’3ax+16xβˆ’47Since the coefficients of the x2-term have to be equal on both sides of the equation, βˆ’8a=24, or a=βˆ’3.The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is th

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