Mathematics: (5x^5) - (80x^3) factoring

Mathematics

29.08.2020 08:02

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(5x^5) - (80x^3) factoring

(5x^5) - (80x^3)
factoring

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zovav1oszg9z

5,0(89 marks)

Factoring the term (5x^5) - (80x^3) we get $\mathbf{5x^3(x-4)(x+4)}$

Step-by-step explanation:

We need to factor the term (5x^5) - (80x^3)

First we can see that 5x^3 is common in both terms

So, taking 5x^3 common:

$(5x^5) - (80x^3)\\=5x^3(x^2-16)$

We can write x^2-16 as (x)^2-(4)^2

=5x^3((x)^2-(4)^2)

Now we can solve (x)^2-(4)^2 using the formula: a^2-b^2=(a+b)(a-b)

We can write:

$=5x^3((x)^2-(4)^2)\\=5x^3(x-4)(x+4)$

So, factoring the term (5x^5) - (80x^3) we get $\mathbf{5x^3(x-4)(x+4)}$

bekzod37

4,8(68 marks)

What is the equation

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(5x^5) - (80x^3) factoring

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