x = 6
m<1 = 20°
m<CFE = 140°
Step-by-step explanation:
m<1 = (3x + 2)°
m<2 = (5x - 10)°
✔️Given that FB bisects AFC, therefore,
m<1 = m<2
Substitute
3x + 2 = 5x - 10
Collect like terms and solve for x
3x - 5x = -2 - 10
-2x = -12
-2x/-2 = -12/-2
x = 6
✔️m<1 = 3x + 2
Plug in the value of x
m<1 = 3(6) + 2
m<1 = 18 + 2
m<1 = 20°
✔️m<CFE = 180° - m<AFC (angles on a straight line)
m<CFE = 180° - (m<1 + m<2)
m<CFE = 180° - (20 + 20)
m<CFE = 180° - 40°
m<CFE = 140°