: (570)=2 م Let m 1 = (342) and m .16 = m1= =OFE هم (​

x = 6

m<1 = 20°

m<CFE = 140°

Step-by-step explanation:

m<1 = (3x + 2)°

m<2 = (5x - 10)°

✔️Given that FB bisects AFC, therefore,

m<1 = m<2

Substitute

3x + 2 = 5x - 10

Collect like terms and solve for x

3x - 5x = -2 - 10

-2x = -12

-2x/-2 = -12/-2

x = 6

✔️m<1 = 3x + 2

Plug in the value of x

m<1 = 3(6) + 2

m<1 = 18 + 2

m<1 = 20°

✔️m<CFE = 180° - m<AFC (angles on a straight line)

m<CFE = 180° - (m<1 + m<2)

m<CFE = 180° - (20 + 20)

m<CFE = 180° - 40°

m<CFE = 140°