3^(2x) = 7^(x-1) how do you solve this

x=−7.74294

Step-by-step explanation:

Let's solve your equation step-by-step.

32x=7x−1

Solve Exponent.

32x=7x−1

log(32x)=log(7x−1)(Take log of both sides)

2x*(log(3))=(x−1)*(log(7))

2x=(

log(7)

log(3)

)*(x−1)

2x=1.771244*(x−1)

2x=1.771244x−1.771244(Simplify both sides of the equation)

2x−1.771244x=1.771244x−1.771244−1.771244x(Subtract 1.771244x from both sides)

0.228756x=−1.771244

0.228756x

0.228756

=

−1.771244

0.228756

(Divide both sides by 0.228756)

x=−7.74294

x=−7.74294

i need this answer

Step-by-step explanation: