Chemistry
12.10.2022 00:57
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2. Determine the heat of reaction (AH,xn) for the process by which hydrazine (N2H4)

2. Determine the heat of reaction (AH,xn) for the process by which hydrazine (N2H4) is formed from its elements:
N2 (g) +
2 H2 (g) →
N2H4 (g)
by using the following thermochemical data:
N H. (g)
+
O2 (g) →
N2 (g)
-
2 H2O(g)
AH - - 622.2 kJ
H2(g) +
1/2 O2 (g)
H2O (g)
AH = - 285.8 kJ
IN
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hail47
hail47
4,6(90 marks)

The heat of reaction : 50.6 kJ

Further explanation

Based on the principle of Hess's Law, the change in enthalpy of a reaction will be the same even though it is through several stages or ways

Reaction

N₂(g) + 2H₂(g) ⇒N₂H₄(l)

thermochemical data:

1. N₂H₄(l)+O₂(g)⇒N₂(g)+2H₂O(l)   ΔH=-622.2 kJ

2. H₂(g)+1/2O₂(g)⇒H₂O(l)  ΔH=-285.8 kJ

We arrange the position of the elements / compounds so that they correspond to the main reaction, and the enthalpy sign will also change

1. N₂(g)+H₂O(l) ⇒  N₂H₄(l)+O₂(g) ΔH=+622.2 kJ

2. H₂(g)+1/2O₂(g)⇒H₂O(l)  ΔH=-285.8 kJ x 2 ⇒

2H₂(g)+O₂(g)⇒2H₂O(l)  ΔH=-571.6 kJ

Add reaction 1 and reaction 2, and remove the same compound from different sides

1. N₂(g)+2H₂O(l) ⇒  N₂H₄(l)+O₂(g) ΔH=+622.2 kJ

2.2H₂(g)+O₂(g)⇒2H₂O(l)            ΔH=-571.6 kJ

+

N₂(g) + 2H₂(g) ⇒N₂H₄(l)   ΔH=50.6 kJ

56340
56340
4,8(90 marks)

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Explanation:

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